C 语言实例 – 计算两个时间段的差值 2021年12月7日 20:55:472021年12月7日一键计算 C语言教程评论2,070 雨后池塘,个人日记空间!点击进入» C 语言实例 - 计算两个时间段的差值 计算两个时间段的差值。 实例 #include <stdio.h> struct TIME { int seconds; int minutes; int hours; }; void differenceBetweenTimePeriod(struct TIME t1, struct TIME t2, struct TIME *diff); int main() { struct TIME startTime, stopTime, diff; printf("输入开始时间: \n"); printf("输入小时、分钟、秒:"); scanf("%d %d %d", &startTime.hours, &startTime.minutes, &startTime.seconds); printf("输入停止时间: \n"); printf("输入小时、分钟、秒: "); scanf("%d %d %d", &stopTime.hours, &stopTime.minutes, &stopTime.seconds); // 计算差值 differenceBetweenTimePeriod(startTime, stopTime, &diff); printf("\n差值: %d:%d:%d - ", startTime.hours, startTime.minutes, startTime.seconds); printf("%d:%d:%d ", stopTime.hours, stopTime.minutes, stopTime.seconds); printf("= %d:%d:%d\n", diff.hours, diff.minutes, diff.seconds); return 0; } void differenceBetweenTimePeriod(struct TIME start, struct TIME stop, struct TIME *diff) { if(stop.seconds > start.seconds){ --start.minutes; start.seconds += 60; } diff->seconds = start.seconds - stop.seconds; if(stop.minutes > start.minutes){ --start.hours; start.minutes += 60; } diff->minutes = start.minutes - stop.minutes; diff->hours = start.hours - stop.hours; } 输出结果为: 输入开始时间: 输入小时、分钟、秒:12 34 55 输入停止时间: 输入小时、分钟、秒: 8 12 5 差值: 12:34:55 - 8:12:5 = 4:22:50 历年同日文章 12 月7 2020Windows必装软件IDM(优秀下载工具)v6.38.14 完美**版 点赞 登录收藏 https://www.gongshiku.com/html/202112/c-yuyanshili-jisuanlianggeshijianduandechazhi.html 复制链接 复制链接 运营不易, 感谢支持! 我的微信 微信号已复制 我的微信公众号 我的微信公众号扫一扫 我的公众号 公众号已复制